How to check the dfifferentiability of f(x) where f(x)=|2x-3| at x=1?

1 Answer
Ananda Dasgupta
May 9, 2018

The function is differentiable at #x=1#

Explanation:

#f(x) = |2x-3| # is equal to #3-2x# for #x<3/2#, and so, there is an open interval around #x=1# where it is given by #3-2x#

So, the derivative exists and is equal to -2

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