How to convert #r=8+3costheta# to rectangular form?

Sorry, another of these questions. I can't figure out what I'm supposed to do with it so any help is appreciated.

1 Answer
May 14, 2018

#(x^4+2x^2y^2-6x^3+y^4-6y^2x-55x^2)/64= y^2#

Explanation:

#r=8+3costheta#

#r^2=8r+3rcostheta#

#x^2+y^2= 8r+3x#

#(x^2+y^2-3x)^2= (8r)^2#

#x^4+2x^2y^2-6x^3+y^4-6y^2x+9x^2= 64(x^2+y^2)#

#(x^4+2x^2y^2-6x^3+y^4-6y^2x-55x^2)/64= y^2#

This one works and gives me a limacon
graph{ (x^4+2x^2y^2-6x^3+y^4-6y^2x-55x^2)/64= y^2 [-15.31, 22.65, -9.6, 9.38]}