How to differentiate equation x^2 = y^3 with respect to t?
I think it can be differentiated like # 2 dx/dt = 3y^2 dy/dt# but in the solution, the equation has been rearranged to #x=y^(3/2)# and then differentiated. I think the answer should still be same but I'm getting different answers for both. Which one is correct?
I think it can be differentiated like
1 Answer
Jan 28, 2018
See below
Explanation:
You made little mistake in differentiating
The answer is ,