How to differentiate y = cos ^-2 ( x )?

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Differentiate y = cos ^-2 ( x )

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Answer 1 · 2018-04-21T18:00:07

#y=cos^-2x=>(dy)/(dx)=-2cos^-3x(-sinx)=(2sinx)/cos^3x#
#=>(dy)/(dx)=2*1/cos^2xsinx/cosx=2sec^2xtanx#
#:.(dy)/(dx)=2sec^2xtanx#

#y = cos ^-2 ( x )#

#=>y=(cosx)^-2#

#=>y=1/(cosx)^2#

#=>y=1/cos^2x#

#=>y=sec^2x#

#=>(dy)/(dx)=2secxd/(dx)(secx)#

#=>(dy)/(dx)=2secxsecxtanx#

#=>(dy)/(dx)=2sec^2xtanx#