How to differentiate y= sin (#-5x^2-8x+2#) ?

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Answer 1 · 2018-04-21T07:19:09

See explanation.

The function is a composition of #2# functions, so to differentiate it you have to use the Chain rule.

The rule says that:

#[f(g(x))]^'=f^'(g(x))*g'(x)#

So in the given example you have:

#[sin(-5x^2-8x+2)]^'=#
#=cos(-5x^2-8x+2)*(-10x-8)#