How to express the following in terms of x ?

#log_n# 6 = x

(#log_n# 3)^2 + (#log_n# 2)(#log_n# 18)

1 Answer
Cesareo R.
Aug 23, 2017

#x^2#

Explanation:

#(log_n6-log_n2)^2+log_n 2(log_n 3+log_n 6)=#

#=(log_n6-log_n2)^2+log_n 2(log_n 6-log_n 2+log_n 6) =#

#(log_n6)^2-2 log_n 2 log_n 6 + (log_n 2)^2+2 log_n 2 log_n 6 -(log_n 2)^2 = (log_n6)^2 = x^2#

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