Question

How to find critical points and the using the first derivative test for `f(x) = 3x^4 - 4x^3 + 6`?

Answer 1

`f(x) = 3x^4 - 4x^3 + 6`
Derivative: `f'(x) = 12x^3 - 12x^2 = 12x^2*(x - 1)`
`f'(x) = 0` when `x = 0` and `x = 1`. The critical points are: `(0, 6)` and `(1, 5).`