Question

How to find dimensions of a rectangle with a perimeter of 24m?

Answer 1

Any lengths/widths satisfying the equation

`l+w=12`

Explanation:

We know that perimeter is given by

`2l+2w`

where `l` is the length and `w` is the width. We are saying the perimeter is equal to `24`, so we have the following equation:

`2l+2w=24`

Both terms have a `2` in common, so we can factor that out. We get

`2(l+w)=24`

Dividing both sides by `2`, we get

`l+w=12`

The length and the width must sum up to `12`. Any combinations will yield a perimeter of `24`.

If `l=8` and `w=4`, then we have

`2(8)+2(4)`

which simplifies to

`16+8=color(blue)(24)`

Notice that `8` and `4` sum up to `12`. So any combination of numbers that add up to `12` will be our dimensions.

Hope this helps!