How to find out the breakdown voltage?
answer is 4 KV
answer is 4 KV
1 Answer
Apr 23, 2018
Explanation:
In a series combination of capacitors, the voltage is divided in inverse ratio of the capacitance.
If
- the voltage applied across
#6\ mu"F"# is#2/(2+6)V=1/4V# - that across
#2\ mu"F"# is#6/(2+6)V=3/4V# - that across
#3\ mu"F"# is#1/(3+1)V=1/4V# - that across
#1\ mu"F"# is#3/(3+1)V=3/4V#
Now,
- For the
#6\ mu"F"# capacitor to break down, the applied voltage must be#4times 1\ "kV"=4\ "kV"# -
For the
#2\ mu"F"# capacitor to break down, the applied voltage must be#4/3times 4\ "kV"=16/3\ "kV"# -
For the
#3\ mu"F"# capacitor to break down, the applied voltage must be#4times 4\ "kV"=16\ "kV"# -
For the
#1\ mu"F"# capacitor to break down, the applied voltage must be#4/3times 5\ "kV"=20/3\ "kV"#
The breakdown voltage for the circuit is the least of these values :