How to find the derivative of x^3+y^3=1 by using the implicit differentiation ?

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Answer 1 · 2015-04-27T02:10:02

Considering that #y# is function of #x# you have:
#3x^2+3y^2(dy)/(dx)=0#
And:
#(dy)/(dx)=-x^2/y^2#