How to find x(t) and y(t)?
Consider the trajectory of a golf ball which will be hit with a club, where the initial speed of the ball is #v_o# and the angle at which the golf ball leaves the golf club is #alpha# . Assume that the horizontal acceleration is #a_x=-kv_x^2# (where #v_x# is the horizontal speed) and vertical acceleration is only due to gravity #g# .
Find expressions for x and y positions of a ball as a function of time #t# , in terms of the initial conditions for the ball #v_o# , #alpha# , and the aerodynamic drag coefficient #k# .
Answer: #x(t)=1/kln(ktv_ocosalpha+1)# , #y(t)=-1/2g t^2+v_otsinalpha#
Consider the trajectory of a golf ball which will be hit with a club, where the initial speed of the ball is
Find expressions for x and y positions of a ball as a function of time
Answer:
1 Answer
As below.
Explanation:
Let us look at the following figure to see the initial conditions.
It does not depict the actual trajectory followed by the golf ball.
Since both
- Displacement along
#y# axis.
We may use the kinematic equation
#s=ut+1/2at^2# , ......(1)
where#s# is the distance moved in time#t# ,#u# is initial velocity and#a# is the acceleration. Inserting given values we obtain
#y(t)=(v_@sin alpha)t-1/2g t^2#
#-# sign in front of acceleration due to gravity#g# shows that it is in#-y# direction or opposite to the direction of displacement in the#y# direction. Rearranging
- Displacement along
#x# axis
Now we are to find out
We know that
So
or
Integrating both sides
Imposing boundary condition: at
From (3) we have
Inserting this value of
Now inserting this value of
Now let
when
Differentiating (5) w.r.t to respective variables we get
Now equation(4) becomes