How to make these molecules from cyclopentene?

Starting from cyclopentene how would you prepare these molecules:

a) chlorocyclopentane
b) 3-bromocyclopentane
c) cyclopentanol
d) cyclopentylcyclopentan

1 Answer
Jun 18, 2017

#a)#

Chlorocyclopentane will have no specific designation as to which carbon is carbon-1, so it does not matter which atom in the double bond is chlorinated. Aqueous #"HCl"# would do the trick.

#b)#

3-bromocyclopentane is the same as bromocyclopentane. I think you may mean 3-bromocyclopentene, where the 3 has a meaning.

To do this, using #N#-bromosuccinimide with a peroxide and light or heat puts a bromine atom on the allylic carbon (one atom away from an alkene carbon).

Since cyclopentene has a reflection plane bisecting its double bond, the regular product and the resonance product (where the double bond conjugates down to be across carbon-3 and carbon-2) are identical.

If you mean the alkane, just finish by subsequently adding #H_2# catalyzed by #Pd# over #C#.

#c)#

Similar to #(a)#, it does not matter which alkene carbon gets the #"OH"#, so simple acid-catalyzed hydration---which is Marknovnikov---works just fine (rather than, say, hydroboration-oxidation, which is anti-Markovnikov), i.e. #"H"_2"O"# and #"H"_2"SO"_4#.

It would work better if the #"H"_2"SO"_4# were dilute.

#d)#

This one's kinda tricky, and requires you to look for a specific reaction to do in one step.

You can do this with a Gilman reagent, which is most useful for coupling two alkyl groups starting from an alkyl halide and an alkyllithium reagent.

If you prepare your Gilman reagent:

#2"cyclopentylLi" + "CuI" stackrel("THF"" ")(->) ("cyclopentyl")_2"CuLi" + "LiI"#

then you can use it with the newly-formed bromocyclopentane dissolved in #"THF"# to dimerize and form your cyclopentylcyclopentane.