How to prove or dis prove ? #if lim_(x->a)f(x)=b and lim_(x->b)g(x)=c# then #lim_(x->a)g๐f(x)=c#

1 Answer
Oct 28, 2017

See the explanation below

Explanation:

This is the limit of the composition of functions

#lim_(x->a)f(x)=b#

#lim_(x->b)g(x)=c#

Therefore,

#lim_(x->b) go f(x)=g(lim_(x->a)f(x))=c#

because #f(x)# is approaching #a# and we are evaluating #g# at #f(x)# and this is the same as

#lim_(x->b)g(x)=c#