How to rewrite the function #d(theta)= (x^2sin(theta)cos(theta))/4.9# so it involves a single trigonometric function?

1 Answer
Ratnaker Mehta
Mar 14, 2018

# d(theta)=(x^2sin2theta)/9.8#.

Explanation:

We know that, #sin2theta=2sinthetacostheta#.

#:. d(theta)=(x^2sinthetacostheta)/4.9#,

#=(x^2sinthetacostheta)/4.9xx2/2#,

#={x^2(2sinthetacostheta)}/(2xx4.9)#.

# rArr d(theta)=(x^2sin2theta)/9.8#, is the desired expression!

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