How to solve #1/2 +x/3 +x^2/4# where #x=1/2#? Please show steps.

1 Answer
Sep 8, 2015

Answer:

#1/2+x/3+x^2/4# with #x=1/2#
#color(white)("XXXXXXXXXXXXXXXX")=35/48#

Explanation:

Given #1/2+x/3+x^2/4# with #x=color(red)(1/2)#

#1/2+color(red)(1/2)/3+(color(red)(1/2))^2/4#

#=1/2+color(blue)((1/2)/3)+color(green)((1/4)/4)#

#=1/2+color(blue)(1/2*1/3)+color(green)((1/4)*1/4)#

#=1/2+color(blue)(1/6) + color(green)(1/16)#

least common multiple is #3xx16 = 48#

#color(blue)(1/2)+color(orange)(1/6) + color(green)(1/64)#

#=color(blue)(24/48)+color(orange)(8/48) + color(green)(35/48)#

#=35/48#