How to solve for x if #x^2+(2/3)x-1/3=0# ?
1 Answer
Apr 10, 2018
Explanation:
#"take out a "color(blue)"common factor "1/3#
#rArr1/3(3x^2+2x-1)=0#
#"factor the quadratic using the a-c method"#
#"the factors of the product "3xx-1=-3" which sum"#
#"to + 2 are + 3 and - 1"#
#"split the middle term using these factors"#
#3x^2+3x-x-1=0larrcolor(blue)"factor in groups"#
#color(red)(3x)(x+1)color(red)(-1)(x+1)=0#
#"take out the common factor "(x+1)#
#rArr(x+1)(color(red)(3x-1))=0#
#"equate each factor to zero and solve for x"#
#x+1=0rArrx=-1#
#3x-1=0rArrx=1/3#