How to solve lim_(xto0)(ln cotx)^tanx?

1 Answer
Mar 5, 2018

lim_(x->0)(lncotx)^tanx=1

Explanation:

lim_(x->0)tanx=0

lim_(x->0^+)cotx=+oo
lim_(x->0^-)cotx=-oo

lim_(x->+oo)ln(x)=oo

oo^0=1 since a^0=1,a!=0 (we'll say a!=0, since it get's a little bit complicated otherwise, some say it is 1, some say 0, others say it is undefined, etc.)