How to solve polynomial multiple choices?
Can someone please explain to me where I went wrong with question 9 and 10? I picked A and D. Thanks!
Can someone please explain to me where I went wrong with question 9 and 10? I picked A and D. Thanks!
1 Answer
Dec 22, 2017
Explanation:
#(9)to(A)#
#(10)to(B)#
#(x^2+a)(x-b)(x+c)=0#
#"equate each factor to zero and solve for x"#
#x^2+a=0rArrx^2=-a#
#"this has no real solutions"#
#x-b=0rArrx=b in RR^+#
#x+c=0rArrx=-c !inRR^+#
#rArr"equation has only 1 valid solution "to(B)#