How to solve polynomial multiple choices?
Can someone please explain to me where I went wrong with question 9 and 10? I picked A and D. Thanks!
Can someone please explain to me where I went wrong with question 9 and 10? I picked A and D. Thanks!
1 Answer
Dec 22, 2017
Explanation:
(9)to(A)(9)→(A)
(10)to(B)(10)→(B)
(x^2+a)(x-b)(x+c)=0(x2+a)(x−b)(x+c)=0
"equate each factor to zero and solve for x"equate each factor to zero and solve for x
x^2+a=0rArrx^2=-ax2+a=0⇒x2=−a
"this has no real solutions"this has no real solutions
x-b=0rArrx=b in RR^+
x+c=0rArrx=-c !inRR^+
rArr"equation has only 1 valid solution "to(B)