How to solve : # (px^2-4+5x)/(p^3x-x^2) = 1# ?

1 Answer
Sunayan S
Apr 6, 2018

#(px^2-4+5x)/(p^3x-x^2)=1#

#=>px^2-4+5x=p^3x-x^2#

#=>px^2-4+5x-p^3x+x^2=0#

#=>(p+1)cdot x^2-(p^3-5)cdot x-4=0#

  • Applying Shreedhar Acharya's Formula,

#x=((p^3-5)+-sqrt((p^3-5)^2+4xx4xx(p+1)))/(2 cdot (p+1)#

#x=((p^3-5)+-sqrt(p^6-10p^3+25+16p+16))/(2 cdot (p+1)#

#x=((p^3-5)+-sqrt(p^6-10p^3+16p+41))/(2 cdot (p+1)#

Related questions
Impact of this question
929 views around the world
You can reuse this answer
Creative Commons License