How to solve the following ?
In Millikan's oil drop experiment on applying a vertically upward electric field an oil drop (of mass m) moves vertically downward with certain terminal speed. On applying double the electric field in horizontal direction the drop moves making 45^@ with vertical. Neglecting buoyant force due to the air, what is the viscous force acting on the drop in first case ??
In Millikan's oil drop experiment on applying a vertically upward electric field an oil drop (of mass m) moves vertically downward with certain terminal speed. On applying double the electric field in horizontal direction the drop moves making
1 Answer
In first case the droplet of mass
If the viscous force exerted by air be
At this state of downard motion of the droplet with terminal velocity
Combining [1] and #[2] we get