How to solve the following simultaneous equations: #2x+y=8# #4x^2+3y^2=52# ??

1 Answer
Dec 20, 2017

Write the linear equation as y in terms of x.
Substitute for y into the elliptic equation.
Solve the resulting quadratic for the values of x.
Use the linear equation to find the y values.

Explanation:

Write the linear equation as y in terms of x.

#y = 8-2x#

Substitute for y into the elliptic equation.

#4x^2+3(8-2x)^2=52#

#4x^2+3(4x^2-32x+64)=52#

#16x^2-96x+140 =0#

Solve the resulting quadratic for the values of x.

#x = (96+sqrt((-96)^2-4(16)(140)))/(2(16))#

and

#x = (96-sqrt((-96)^2-4(16)(140)))/(2(16))#

#x = 7/2# and #x = 5/2#

Use the linear equation to find the y values.

#y = 8-2(7/2)# and #y = 8-2(5/2)#

#y = 1# and #y = 3#

The points of intersection for the line and the ellipse are #(7/2,1)# and #(5/2,3)#