How to solve this?If a #in ZZ_8#is an invertible element,demonstrate that #hat2x=a# don't have solutions #x in ZZ_8#

1 Answer
Apr 7, 2017

See explanation...

Explanation:

If there is an #x# such that:

#hat(2)x = a#

then we find:

#hat(4)a = hat(4)*hat(2)x = hat(8)x = hat(0)x = hat(0)#

Then if #a# had an inverse #a^(-1)#, we would find:

#hat(0) = hat(0)a^(-1) = hat(4)a*a^(-1) = hat(4)*hat(1) = hat(4)" "# which is false.

So there can be no such inverse. That is #a# is not invertable.