# How to solve this?There are three events A,B,C one of which must and only one can happen.The odds are 7 to 3 against A and 6 to 4 against B,find the odds against C

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I cant understand what to take as the favourable event and total event.And how to solve this

I cant understand what to take as the favourable event and total event.And how to solve this

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jakemc8
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Mar 8, 2018

#### Answer:

The odds are 7 to 3 against C.

#### Explanation:

Since it tells you the odds are 7 to 3 against A, that means A has 3/10 chance of happening. It says the odds are 6 to 4 against B; therefore, B has 4/10 chance of happening. Knowing that B has 4/10 chance and A has 3/10 chance, you can add them together to get 7/10. There is a 7/10 chance that either B or A will happen. Keeping this in mind, C would then have the odds stacked against them 7 to 3. I know C only has 3 chances because with the 7/10 chances A and B take up, there are only 3 left.

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