How to state the equivalent expression for cosxtanx?

1 Answer
Nov 19, 2017

sin(x)

Explanation:

One of our most important trig identities is:

tan(x) = sin(x)/cos(x)

Hence, we can rewrite the expression above as:

cos(x)[sin(x)/cos(x)]

Now, the cosines cancel out, so we're just left with:

color(red)cancel(cos(x))[sin(x)/color(red)(cancel(cos(x)))]

=> sin(x)

Hope that helped :)