Question

How to you find the general solution of `dy/dx=x^3-4x`?

Answer 1

`y = 1/4x^4 - 2x^2 + C`

Explanation:

`dy/dx = x^3-4x`

We can just separate the variables "as is":
`int dy = int x^3-4xdx`

And so integrating gives us;
`y = 1/4x^4 - 2x^2 + C`