how would I find range of this e.g (6/(2x+3)) for x>0 I will put zero in place of x and find range that is 2 but I don't know it will be greater or less than x? Precalculus 1 Answer Narad T. Apr 5, 2018 Answer: The range is #y in RR-{0}# Explanation: To find the range, proceed as follows Let #y=6/(2x+3)# #y(2x+3)=6# #2xy+3y=6# #2xy=6-3y# #x=(6-3y)/(2y)# The denominator is #!=0# Therefore, #y!=0# The range is #y in RR-{0}# graph{6/(2x+3) [-18.02, 18.01, -9.01, 9.01]} Related questions How do I determine the molecular shape of a molecule? What is the lewis structure for co2? What is the lewis structure for hcn? How is vsepr used to classify molecules? What are the units used for the ideal gas law? How does Charle's law relate to breathing? What is the ideal gas law constant? How do you calculate the ideal gas law constant? How do you find density in the ideal gas law? Does ideal gas law apply to liquids? Impact of this question 143 views around the world You can reuse this answer Creative Commons License