# How would I graph something like x^2 = 16?

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I don't understand how it would be possible to graph that. It looks like only plus or minus four works in that situation, but how would you graph more than 3 points? (X intercepts, vertex). How would you find that vertex?

I don't understand how it would be possible to graph that. It looks like only plus or minus four works in that situation, but how would you graph more than 3 points? (X intercepts, vertex). How would you find that vertex?

##### 1 Answer

First of all, you are right, the

How to find the vertex:

The vertex is at the halfway point of the zeros. So for the

For the

So the

So we have three points:

Let's see how this looks graphed:

graph{y = x^2-16}