# How would I simplify square root 48+square root 27?

Jul 19, 2015

First try and get some squares out of the root

#### Explanation:

$48 = {4}^{2} \cdot 3 \to \sqrt{48} = \sqrt{{4}^{2}} \cdot \sqrt{3} = 4 \sqrt{3}$

$27 = {3}^{2} \cdot 3 \to \sqrt{27} = \sqrt{{3}^{2}} \cdot \sqrt{3} = 3 \sqrt{3}$

$\sqrt{48} + \sqrt{27} = 4 \sqrt{3} + 3 \sqrt{3} = 7 \sqrt{3}$