How would you calculate the speed (in #m/s#) of a skateboarder who accelerates from rest for 4 seconds down a ramp at an acceleration of #3 m/s^2#?

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Answer 1 · 2018-04-02T10:35:14

Applicable kinematic expression is

#v=u+at#

Inserting given values we get

#v=0+3xx4#
#v=12\ ms^-1#

Answer 2 · 2018-04-02T10:59:51

#12 \ "m/s"#

Using the basic kinematics equation,

#v=u+at#

#u# is the initial speed

#a# is the acceleration

#t# is the time

And so,

#v=0 \ "m/s"+3 \ "m/s"^2*4 \ "s"#

#=12 \ "m/s"#