How would you calculate the standard entropy change for the combustion of methanol at 25 C? #2CH_3OH(lamda) + 3O_2(g) -> 2CO_2(g) + 4H_2O(g)#

enter image source here

1 Answer
Michael
Apr 18, 2017

You would calculate it like this:

Explanation:

#sf(DeltaS^@=Sigma[S^@"products"]-Sigma[S^@"reactants"])#

#sf(DeltaS^@=(2xx213.7+4xx188.8)-(2xx127.2+3xx205.1))#

#sf(DeltaS^@=1,182.6-869.7)#

#sf(DeltaS^@=+312.9color(white)(x)"J""/"K."mol")#

Related questions
See all questions in Entropy
Impact of this question
22405 views around the world
You can reuse this answer
Creative Commons License