How would you calculate the standard entropy change for the combustion of methanol at 25 C? 2CH_3OH(lamda) + 3O_2(g) -> 2CO_2(g) + 4H_2O(g)

Apr 18, 2017

You would calculate it like this:

Explanation:

$\textsf{\Delta {S}^{\circ} = \Sigma \left[{S}^{\circ} \text{products"]-Sigma[S^@"reactants}\right]}$

$\textsf{\Delta {S}^{\circ} = \left(2 \times 213.7 + 4 \times 188.8\right) - \left(2 \times 127.2 + 3 \times 205.1\right)}$

$\textsf{\Delta {S}^{\circ} = 1 , 182.6 - 869.7}$

$\textsf{\Delta {S}^{\circ} = + 312.9 \textcolor{w h i t e}{x} \text{J""/"K."mol}}$