How would you determine the mass of hydrogen produced when 0.25 g of sodium reacts with water? Sodium hydroxide is the other product formed in the reaction.

1 Answer
May 18, 2017

Answer:

Well, our priority is to write a stoichiometric equation..............

Explanation:

#Na(s) + H_2O(l) rarr NaOH(aq) + 1/2H_2(g)uarr#

Given the stoichiometry, HALF AN EQUIV dihydrogen gas is evolved from ONE EQUIV natrium metal.

#"Moles of Na = "(0.25*g)/(22.99*g*mol^-1)=0.0109*mol# WITH RESPECT TO the metal...........

Stoichiometry demands that #(0.0109*mol)/2# #"dihydrogen gas"# is evolved, i.e. #5.44xx10^-3*mol#, a mass of #11*mg#.