How would you draw the resulting carboxylate anion that forms when propanoic acid reacts with a strong base?

1 Answer
Jul 22, 2016

Answer:

#H_3C-CH_2C(=O)OH + NaOH rarr H_3C-CH_2C(=O)O^(-)Na^+ + H_2O#

Explanation:

This is a standard acid base reaction. Propanoic acid is fairly weak, yet will react with sodium hydroxide. Sodium propanoate would give a basic solution in aqueous solution. Why?