# How would you draw the resulting carboxylate anion that forms when propanoic acid reacts with a strong base?

Jul 22, 2016

#### Answer:

${H}_{3} C - C {H}_{2} C \left(= O\right) O H + N a O H \rightarrow {H}_{3} C - C {H}_{2} C \left(= O\right) {O}^{-} N {a}^{+} + {H}_{2} O$

#### Explanation:

This is a standard acid base reaction. Propanoic acid is fairly weak, yet will react with sodium hydroxide. Sodium propanoate would give a basic solution in aqueous solution. Why?