# How would you draw the resulting carboxylate anion that forms when propanoic acid reacts with a strong base?

${H}_{3} C - C {H}_{2} C \left(= O\right) O H + N a O H \rightarrow {H}_{3} C - C {H}_{2} C \left(= O\right) {O}^{-} N {a}^{+} + {H}_{2} O$