How would you evaluate #(5.7×106 kg) × (6.3×10−2 m/s2)# and express the answer in scientific notation?

1 Answer
Mar 29, 2016

Answer:

#3.591xx10^5N#

Explanation:

Probably there is a formatting issue with the question. I will attempt to be a mind-reader and restate as following

Evaluate #(5.7xx10^6kg)xx(6.3xx10^-2ms^-2)# and express the answer in scientific notation

#(5.7xx10^6kg)xx(6.3xx10^-2ms^-2)#, Multiplying numbers and treating powers of #10# separately we obtain

#(5.7xx6.3xx10^6xx10^-2)(kgms^-2)#
#(35.91xx10^6xx10^-2))(kgms^-2)#,
we know that #(kgms^-2)# looks like mass times acceleration and has symbol #"N# for Force.
Also shifting the decimal by one place to the left to represent in scientific notation
#(3.591xx10^1xx10^6xx10^-2)(N)#, adding powers of 10
#(3.591xx10^(1+6-2))N#
#3.591xx10^5N#