How would you rewrite sin(x-pi/3)?

1 Answer

Using the sin difference identity...see below

#color(blue)((sinx-sqrt3cosx)/2#

Explanation:

#sin(theta-alpha)= sintheta*cosalpha-costheta*sinalpha#

So in this case:
#sin(x-pi/3)= sinx*cos(pi/3)-cosx*sin(pi/3)#

But we can simplify:
#sinx*(1/2)-cosx*(sqrt3/2)=#

#(sinx-sqrt3cosx)/2#