# How would you simplify #sqrt48 + sqrt3#?

##### 4 Answers

#### Explanation:

We can split up

Thus,

The original expression can be rewritten as

#4sqrt3+sqrt3=sqrt3(4+1)=5sqrt3#

Short story, try watching the result of division of the two numbers and substitute it in the bigger one.

#### Explanation:

Always try reducing the high number to something of which you know the root. Here someone should notice that:

The root of 16 is known, while the root of 3 can be factored. Therefore:

#5sqrt3 #

#### Explanation:

radicals in simplified form are

#asqrtb #

where a is a rational number.to begin with , simplify

# sqrt48 # by considering the factors of 48 , particularly 'squares'

the factors required here are 16 (square) and 3.

using the following :

# sqrta xx sqrtb hArr sqrtab #

#sqrt48 = sqrt16 xx sqrt3 = 4sqrt3 # hence

#sqrt48 + sqrt3 = 4sqrt3 + sqrt3 = 5sqrt3 #

:)

#### Explanation:

To simplify radicals, we must find first its largest "perfect squares" that evenly divides to simplify.

Since,

PerfectSquares:

we can simplify

we get,

using theorem from above,

simplify,

since the rule of radical signs is just like variables we can combine like terms, with a slight difference.