How would you simplify #(sqrt6 - 4 sqrt 7)(3 sqrt 6 + 2 sqrt7) #? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer F. Javier B. Mar 12, 2018 See process below Explanation: #(sqrt6-4sqrt7)(3sqrt6+2sqrt7)=3sqrt6sqrt6+2sqrt6sqrt7-12sqrt7sqrt6-8sqrt7sqrt7=18-10sqrt6sqrt7-56=-38-10sqrt6sqrt7=-38-10sqrt42=# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 1075 views around the world You can reuse this answer Creative Commons License