How you find the value of m so that the lines with equations #-3y+2x=4# and #mx + 2y = 3# are perpendicular?

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Answer 1 · 2015-02-05T19:13:29

#m=3#

Put both equations into the form #y=mx+c#

#-3y+2x=4#

#3y=2x-4#

#y=2/3x-4/3#

For the 2nd eqn:

#mx+2y=3#

#2y=3-mx#

#y=-m/2x-3/2#

If the lines are perpendicular the product of their gradients = -1

So #-m/2xx2/3=-1#

#m=3#