Question

How you slove this? `lim_(n->oo)cos(pisqrt(4n^2+n+1))`

Answer 1

`1`

Explanation:

Assuming that `n in ZZ`

`lim_(n->oo)cos(pisqrt(4n^2+n+1))=lim_(n->oo)cos(2 pi n sqrt(1+(n+1)/(4n^2))) = cos(2pi n)=1`