Hydrogen and oxygen react chemically to form water. How much water would form if 4.8 grams of hydrogen reacted with 38.4 grams of oxygen?

1 Answer
Sep 5, 2016

Answer:

Approx. #36*g#

Explanation:

We need a stoichiometric equation for water synthesis:

#H_2(g) + 1/2O_2(g) rarr H_2O(l)#

Clearly, dihydrogen must be present in a 2:1 molar ratio with respect to dioxygen.

#"Moles of dihydrogen"# #=# #(4.8*g)/(2.01*g*mol^-1)# #=# #2.39*mol#

#"Moles of dioxygen"# #=# #(38.4*g)/(32.0*g*mol^-1)# #=# #1.2*mol#

Given these molar quantities (they are approx. 2:1) the gases are present in stoichiometric proportion. #2# #mol# water are going to be produced.

#2*molxx18.00*g*mol^-1# #=# #36*g#

Do you think that this would be an exothermic reaction; i.e. do you think that energy would be released by the reaction?