Hydrogen and oxygen react chemically to form water. How much water would form if 4.8 grams of hydrogen reacted with 38.4 grams of oxygen?

Question

8576 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-09-05T06:24:12

Approx. #36*g#

We need a stoichiometric equation for water synthesis:

#H_2(g) + 1/2O_2(g) rarr H_2O(l)#

Clearly, dihydrogen must be present in a 2:1 molar ratio with respect to dioxygen.

#"Moles of dihydrogen"# #=# #(4.8*g)/(2.01*g*mol^-1)# #=# #2.39*mol#

#"Moles of dioxygen"# #=# #(38.4*g)/(32.0*g*mol^-1)# #=# #1.2*mol#

Given these molar quantities (they are approx. 2:1) the gases are present in stoichiometric proportion. #2# #mol# water are going to be produced.

#2*molxx18.00*g*mol^-1# #=# #36*g#

Do you think that this would be an exothermic reaction; i.e. do you think that energy would be released by the reaction?