# The price of a stock, A(x), over a 12-month period decreased and then increased according to the equation... ?

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The price of a stock, A(x), over a 12-month period decreased and then increased according to the equation, A(x)=#0.75x^2−6x+20# , where x equals the number of months. The price of another stock, B(x), increased according to the equation B(x)= 2.75x+1.50 over the same 12-month period. Graph and label both equations on the accompanying grid. State all prices, to the nearest dollar, when both stock values were the same.

The price of a stock, A(x), over a 12-month period decreased and then increased according to the equation, A(x)=

##### 1 Answer

#### Answer:

The stock values are the same for

#### Explanation:

Plot the graph of

graph{0.75x^2-6x+20 [-10.33, 40.98, -3.18, 22.5]}

Then plot

graph{2.75x+1.50 [-13.7, 51.24, -0.84, 31.67]}

Then,

plot the graphs on the same plot

graph{(y-0.75x^2+6x-20)(y-2.75x-1.50)=0 [-6.92, 33.61, 6.85, 27.16]}

The points of intersections are

and