# The price of a stock, A(x), over a 12-month period decreased and then increased according to the equation... ?

## The price of a stock, A(x), over a 12-month period decreased and then increased according to the equation, A(x)=0.75x^2−6x+20 , where x equals the number of months. The price of another stock, B(x), increased according to the equation B(x)= 2.75x+1.50 over the same 12-month period. Graph and label both equations on the accompanying grid. State all prices, to the nearest dollar, when both stock values were the same.

Jul 29, 2018

#### Answer:

The stock values are the same for =$9 and =30$

#### Explanation:

Plot the graph of

$A \left(x\right) = 0.75 {x}^{2} - 6 x + 20$

graph{0.75x^2-6x+20 [-10.33, 40.98, -3.18, 22.5]}

Then plot

$B \left(x\right) = 2.75 x + 1.50$

graph{2.75x+1.50 [-13.7, 51.24, -0.84, 31.67]}

Then,

plot the graphs on the same plot

graph{(y-0.75x^2+6x-20)(y-2.75x-1.50)=0 [-6.92, 33.61, 6.85, 27.16]}

The points of intersections are

$C = \left(2.774 , 9.128\right)$

and

$D = \left(8.893 , 29.956\right)$