# The price of a stock, A(x), over a 12-month period decreased and then increased according to the equation... ?

## The price of a stock, A(x), over a 12-month period decreased and then increased according to the equation, A(x)=0.75x^2−6x+20 , where x equals the number of months. The price of another stock, B(x), increased according to the equation B(x)= 2.75x+1.50 over the same 12-month period. Graph and label both equations on the accompanying grid. State all prices, to the nearest dollar, when both stock values were the same.

Jul 29, 2018

The stock values are the same for =$9 and =30$

#### Explanation:

Plot the graph of

$A \left(x\right) = 0.75 {x}^{2} - 6 x + 20$

graph{0.75x^2-6x+20 [-10.33, 40.98, -3.18, 22.5]}

Then plot

$B \left(x\right) = 2.75 x + 1.50$

graph{2.75x+1.50 [-13.7, 51.24, -0.84, 31.67]}

Then,

plot the graphs on the same plot

graph{(y-0.75x^2+6x-20)(y-2.75x-1.50)=0 [-6.92, 33.61, 6.85, 27.16]}

The points of intersections are

$C = \left(2.774 , 9.128\right)$

and

$D = \left(8.893 , 29.956\right)$