I'm stuck need help please. #(a^3+8)/( a+2)# ?

1 Answer
Aug 11, 2017

#a^2 +2a+4#

Explanation:

The numerator is the sum of cubes which can be factored:

#color(blue)((a^3+8))/(a+2) = (color(blue)((a+2)(a^2+2a+4)))/((a+2))#

Now cancel the like factors:

#=(cancel((a+2))(a^2+2a+4))/(cancel((a+2)))#

#=a^2 +2a+4#