Question

I need help with this problem please? `14-1/5(j-10)=2/5(25+j)`

Answer 1

`color(magenta)(j=10`

Explanation:

`14-1/5(j-10)=2/5(25+j)`

[Distributive Property]

`=>14-1/5xxj+1/5xx10=2/5xx25+2/5xxj`

`=>14-j/5+2=10+(2j)/5`

`=>16-10=(2j)/5+j/5`

`=>6=(3j)/5`

`=>3j=6xx5`

`=>3j=30`

`=>j=30/3`

`color(magenta)(=>j=10`

~Hope this helps! :)

Answer 2

In this equation `j=10`

Explanation:

1. In this equation, we want to get `j` onto one side of the equation by itself.

2. In order to do this we are going to distribute the `-1/5` throughout the parentheses on the left side of equation giving us `14-1/5j+2` (pay close attention to the negative sign).
   On the other side we're going to distribute the `2/5` through the parentheses on the right side of the equation giving us `10+2/5`j.

3. So at the moment we have `14-1/5j+2=10+2/5j`.

4. Now in order to get `j` by itself on one side were are going to add `1/5j` to both sides of the equation giving us `14+2=10+3/5j`

5. Then we are going to subtract 10 from both sides of the equation giving us `6=3/5j`

6. Now here comes the tricky part (please pay close attention), since `j` is a fraction, we are going to multiply both side of the equation by its reciprocal fraction to give us `1 x j` (any number multiplied by its reciprocal gives you `1`) giving us:
   `(5/3)6=(5/3)(3/5)j`.

7. Simplifying this give the answer `10=j`.