I need to rewrite the expression as a single logarithm. How can I do that? Thanks!
1 Answer
Nov 9, 2017
Explanation:
#"using the "color(blue)"laws of logarithms"#
#•color(white)(x)logx^nhArrnlogx#
#•color(white)(x)logx+logyhArrlog(xy)#
#•color(white)(x)logx-logyhArrlog(x/y)#
#rArr1/3lnx+4[ln(x-3)-ln(x+3)^(3/8)]#
#=1/3lnx+4[ln((x-3)/((x+3)^(3/8)))]#
#=1/3lnx+4ln[((x-3))/((x+3)^(3/8))]#
#=1/3lnx+ln[(x-3)/(x+3)^(3/8)]^4#
#=1/3lnx+ln[(x-3)^4/(x+3)^(3/2)]#
#=lnx^(1/3)+ln[(x-3)^4/(x+3)^(3/2)]#
#=ln[(x^(1/3)(x-3)^4)/(x+3)^(3/2)]]#
#=ln[(root(3)(x)(x-3)^4)/sqrt((x+3)^3)]#