Question

I need to solve this equation. How to I get the bases the same? e^-2x = 1/3

Answer 1

`x=(ln(1/3))/-2`

Explanation:

Given: `e^(-2x)=1/3`

Take natural logs on both sides.

`ln(e^(-2x))=ln(1/3)`

`-2xlne=ln(1/3)`

`-2x=ln(1/3)`

`x=(ln(1/3))/-2`