If 0.30mol of Zn is added to hydrochloride acid containing 0.52 mol of HCl, how many moles of H2 are produced? ( what is the theoretical yield of H2 produced in the reaction?

1 Answer
anor277
Mar 21, 2018

Approx. #0.26*mol# dihydrogen gas.

Explanation:

We start with the stoichiometric equation...

#Zn(s) +2HCl(aq) rarr ZnCl_2(aq) + 2H_2(g)#

We have not got stoichiometric acid, and thus #HCl# is the limiting reagent.... And so if we gots #0.52*mol# #HCl# to begin...we should evolve #0.26*mol# of dihydrogen gas given the stoichiometry....

All I do is follow the equation...obviously a question like this can be expanded to ask for the VOLUME of dihydrogen gas evolved under given conditions....

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