If #(1+x)^n=c_0+c_1x+c_2x^2+cdots+c_nx^n# then show that #c_0+3c_1+5c_2+cdots+(2n+1)c_n=(n+1)2^n#?
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If #(1+x)^n =C_0+C_1x+C_2x^2+cdots+C_nx^n# then show that #C_0+3C_1+5C_2+cdots+ (2n+1)C_n=(n+1)2^n#
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If
1 Answer
Nov 18, 2017
See below.
Explanation:
Taking now
we have also
and making now