Question

If 10^9 electrons move out of a body to the another body every second, how much time is required to get a total charge of 1 C on the other body?

Answer 1

`6.25*10^9` seconds

Explanation:

One electron `(e^-)` has a charge of `1.6*10^-19 \ "C"`.

So here, we would get a charge of `10^9*1.6*10^-19 \ "C"=1.6*10^-10 \ "C"` every second.

And so, we get:

`1color(red)cancelcolor(black)"C"*(1 \ "s")/(1.6*10^-10color(red)cancelcolor(black)"C")=6.25*10^9 \ "s"`

Answer 2

`6.25 × 10^9\ "s"`

Explanation:

Charge of one electron`= 1.6 × 10^-19\ "C"`

Charge of `10^9` electrons

`= (1.6 × 10^-19\ "C")/(1 cancel"electron") × 10^9\ cancel"electrons" = 1.6 × 10^-10\ "C"`

We can say, `1.6 × 10^-10\ "C"` of charge move out of the body to another body every second.

Time required to get a total charge of `"1 C"` is

`(1 cancel"C")/(1.6 × 10^-10 cancel"C"//"s") = underline(6.25 × 10^9\ "s")`