If #17^m=6#, what is m?

1 Answer
Jun 26, 2017

Answer:

#m = ln(6)/ln(17)#

Explanation:

Given #17^m=6#

Use the natural logarithm on both sides:

#ln(17^m) = ln(6)#

NOTE: You can use any base logarithm you like; I have arbitrarily chosen natural logarithms.

Use the property of logarithms #ln(a^c) = cln(a)#:

#mln(17) = ln(6)#

Divide both sides by #ln(17)#

#m = ln(6)/ln(17)#