Question

If 226 kJ of heat increases the temperature of 47.0 kg of copper by 12.5 degree celcius, what is the molar heat capacity of copper?

Answer 1

Recall,

`q = mC_sDeltaT`

Let's derive the specific heat, first,

`=> C_s = q/(mDeltaT) approx (0.385"J")/(g*°"C")`

and convert it to the molar heat capacity,

`(0.385"J")/(g*"C") * (63.5"g")/"mol" approx (24.4"J")/("mol"*°"C")`

which is the molar heat capacity of copper given your data.

This is normally cited `+-0.15` of our calculation.