Question

If 23.5 moles of an ideal gas occupies 93.5 liters at 459 K, what is the pressure of the gas?

Answer 1

We can simply apply ideal gas equation to calculate the pressure of the gas,

So, `PV=nRT`

Given, `V=93.5 L,T=459K, n=23.5`

And, `R=0.0821 L` `atm` `K^-1` `mol^-1`

So,`P= (23.5*459*0.0821)/93.5=9.470 atm`